2[d-(2d+10)+7]=2(d+3)

Solution for 2[d-(2d+10)+7]=2(d+3) equation:

Simplifying
2[d + -1(2d + 10) + 7] = 2(d + 3)

Reorder the terms:
2[d + -1(10 + 2d) + 7] = 2(d + 3)
2[d + (10 * -1 + 2d * -1) + 7] = 2(d + 3)
2[d + (-10 + -2d) + 7] = 2(d + 3)

Reorder the terms:
2[-10 + 7 + d + -2d] = 2(d + 3)

Combine like terms: -10 + 7 = -3
2[-3 + d + -2d] = 2(d + 3)

Combine like terms: d + -2d = -1d
2[-3 + -1d] = 2(d + 3)
[-3 * 2 + -1d * 2] = 2(d + 3)
[-6 + -2d] = 2(d + 3)

Reorder the terms:
-6 + -2d = 2(3 + d)
-6 + -2d = (3 * 2 + d * 2)
-6 + -2d = (6 + 2d)

Solving
-6 + -2d = 6 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-6 + -2d + -2d = 6 + 2d + -2d

Combine like terms: -2d + -2d = -4d
-6 + -4d = 6 + 2d + -2d

Combine like terms: 2d + -2d = 0
-6 + -4d = 6 + 0
-6 + -4d = 6

Add '6' to each side of the equation.
-6 + 6 + -4d = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -4d = 6 + 6
-4d = 6 + 6

Combine like terms: 6 + 6 = 12
-4d = 12

Divide each side by '-4'.
d = -3

Simplifying
d = -3